Algebra

br JavaScript is required for your course . ensure JavaScript is enabled in your nett browser preferencesSeminar on Slope , Equations of Lines and Systems of EquationsTo earn seminar credit for this social unit , cope one of the following options belowOption 1 : Participate in a synchronous seminar (Note : Students are encouraged to attend seminar that the savant may complete Option 2 or else of attend seminarThe seminar s is Slope , Equations of Lines and Systems of Equations complete the Unit 4 practice session onward attending the seminar session in to be known with the indispensable terminology and concepts . Concepts and example capers give be discussed supplementing the sensible cover by the textbookOption 2 : Complete the entire problem dictated below 1 . Find the inc frontier of the logical argument that pa sses with the points (4 , -7 ) and (-2 , -5Solution : The run of the line m is calculated belowm (-5 ) - (-7 (-2 ) - 4 2 (-6 - (1 /32 . Find the equation of the line with a slope of -5 and passes through the point (2 , -4Solution : Equation of the line can be scripted asy - (-4 (-5 (x - 2i .e . y 4 -5x 10i .e . y -5x 63 . bring through an equation of the line that passes through (0 , -4 ) and is jibe y (3 /4 )x 2 . Write the answer in slope-intercept formSolutionAs this lime is agree to y (3 /4 )x 2 therefore , its slope will beAs , it passes through (0 , -4 , therefore , its equation can be indite asy - (-4 (3 /4 (x - 0i .e . y 4 (3 /4 )xi .

e . y (3 /4 )x - 44 .! exercise the system of equations by substitutionx 2y 93x - y 13SolutionGiven , x 2y 9 (13x - y 13 (2From (2 , y 3x - 13 (3By (3 ) in (1 , x 2 (3x - 13 9i .e . x 6x -26 9i .e .7x 35Hence ,x 5Putting x 5 in (3 , y 3 5 - 13 2Therefore , the solution is x 5 and y 25 . discharge the system of equations by substitution4x - 3y 112x - 9y 3SolutionGiven , 4x - 3y 1 (112x - 9y 3 (2From (2 , y (1 /9 (12x - 3 (3By (3 ) in (1 , 4x - 3 (1 /9 (12x - 3 1i .e . 4x - 4x 1 1i .e .1 1This is an identity . This has resulted because equations (1 ) and (2 ) are identical . Therefore , no incomparable solutions rather there are infinitely umpteen solutions for this circle of simultaneous equations . The solution is a straight line in x-y planeThe solution will be of the form y (1 /3 (4x - 1...If you want to get a full essay, inn it on our website: OrderCustomPaper.com

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